△APBと△PAQは同じ長さの辺の二等辺三角形なので、∠BPA=∠QAP
これはPBとAQの錯角なので、PB//AQ
仮定からBP=AQなので、
1組の向かい合う辺が等しくて平行なので、平行四辺形
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△APBと△PAQは同じ長さの辺の二等辺三角形なので、∠BPA=∠QAP
これはPBとAQの錯角なので、PB//AQ
仮定からBP=AQなので、
1組の向かい合う辺が等しくて平行なので、平行四辺形
Users viewing this question
are also looking at these questions 😉
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