Chemistry
Senior High
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この問題を比例式で解く時、どのような式になるか教えて欲しいです🙇‍♀️

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✨ Best Answer ✨

-SO₃H=32+16×3+1.0=81[g/mol]
10g×4.81%/100=0.481g
0.481[g]/81[g/mol]=5.93×10⁻³[mol]
Na⁺:H⁺=1:1
Na⁺=H⁺=5.93×10⁻³mol
5.93×10⁻³[mol]:x[mL]=0.20[mol]:10³[mL]
x=5.93/0.20=29.7≒30[mL]

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