Mathematics
Junior High
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Answers

ABD=ADB
52+ABD+ADB=180
ABD=ADB=64
ABD+ACD+BAC=ABD+ACD+(BAD+x)=180
64+28+52+x=180
×=36

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∠ABD+∠ADB=180-52=128
∠ABD=∠ADB=128÷2=64
∠ADC=180-∠ADB=180-64=116
これで分かりますかね?

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ABDはAB=ADの二等辺三角形なので∠ABD=∠ADB
よって∠ABD=∠ADB=(180-52)÷2=64
∠ADC=180-64=116
180-28-116=36です!

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