Answers
Answers
ABD=ADB
52+ABD+ADB=180
ABD=ADB=64
ABD+ACD+BAC=ABD+ACD+(BAD+x)=180
64+28+52+x=180
×=36
ABDはAB=ADの二等辺三角形なので∠ABD=∠ADB
よって∠ABD=∠ADB=(180-52)÷2=64
∠ADC=180-64=116
180-28-116=36です!
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
証明 定義・ 性質まとめ
8
9
