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∠BFC'=180°-2∠C'FE=22°
x=∠C'BF+∠BFC'=90°+22°=112°
解けました!!!ありがとうございます、わかりやすかったです！！m(__)m
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∠BFC'=180°-2∠C'FE=22°
x=∠C'BF+∠BFC'=90°+22°=112°
解けました!!!ありがとうございます、わかりやすかったです！！m(__)m
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are also looking at these questions 😉
![中学3年2次方程式の問題です。
問題文の[1つだけ整数の解をもつとき]と[2つの異なる整数... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1808181/thumb_l_webp_17834198910490.webp?Expires=1783572538&Signature=fLlWtPavC84DUuWVQW3LaJjxwldhXnu7XRja3teeoXp1BsYZKCYfQlIjilD1MkAtuG3dPC-M1Jxb4SVpeWdBPzuFBbD7B8YpU2T2K7aDuXlN7f18yaLmWMZ6hBmijVBbPVbZAqD75JGhoP6xIWwX3-MLmFTZOqeEYgbpnHsmx~1zwyG3mzn-qubsIHw8mNge5~kz79rFaDyDao2anU64z-z02oKaPTKWf5sa4Ve6K8YlVmQcDCCYcV-0L734h1jcFaDsBh27VewbFieWTB9bMXPyXUZ2hxCGwn74kIbIAyd6px3hUvOCEpIV~6bR5CSS6pZzENZxtd5LOE0qD04Dkg__&Key-Pair-Id=K2W722D70GJS8W&Expires=1783572538&Signature=yCckqR3Yk5sFNKPlZhIA2A4wnJtjF60Mb1J8YzwwFBcXNcat5coI9mRV-mjtiZCx9mNnJCnyNUBa1tPJwv9y9OU4GYeoHPhuJlGj-ILsHiIDp1K3l0FBiKc9OGknMlBMIZB7R-~2-8pAKnudFqICMW7lMfOe3uxJELYI698t5tGv3rOyh2JNumz3g90JDxeIjW14TLI5-SoqsXeULNXjiqpHiP6e7Sk0nwRvE7D3VxfdDvNcd9UeRnAg-EGQyrQn25jF7JIgI2XZilgXJAcmQy2OEGIGD6EZrMmmlOUvgm71jPWCdHuWgVVqoEAJE9fGV7BZgDyo1WX7okgmpWmcHQ__&Key-Pair-Id=K2W722D70GJS8W)
説明すごくわかりやすいです...!折ったの全般すごく苦手なのでありがたいです、、ありがとうございます😢😢