✨ Best Answer ✨
=a(b²-c²)+bc²-ba²+ca²-b²c
=(c-b)a²+(b+c)(b-c)a+bc(c-b)
=(c-b)a²-(c+b)(c-b)a+bc(c-b)
=(c-b)(a²-(c+b)a+bc)
=(c-b)(a-c)(a-b)
=-(b-c)×(-(c-a)×(a-b)
=(a-b)(b-c)(c-a)
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答えは(a-b)(b-c)(c-a)です。
✨ Best Answer ✨
=a(b²-c²)+bc²-ba²+ca²-b²c
=(c-b)a²+(b+c)(b-c)a+bc(c-b)
=(c-b)a²-(c+b)(c-b)a+bc(c-b)
=(c-b)(a²-(c+b)a+bc)
=(c-b)(a-c)(a-b)
=-(b-c)×(-(c-a)×(a-b)
=(a-b)(b-c)(c-a)
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細かく式を書いていただきありがとうございます💦
とても分かりやすいです‼︎