Answers
a+b=xとおく
(x+c)³=x³+3x²c+3xc²+c³
x³=(a+b)³=a³+3a²b+3ab²+b³
x²=(a+b)²=a²+2ab+b²
(a+b+c)³=a³+3a²b+3ab²+b³+3a²c+6abc+3b²c+3ac²+3bc²+c³
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
9000
117
詳説【数学Ⅰ】第二章 ２次関数（後半）～最大・最小・不等式～
6138
25
詳説【数学Ａ】第１章 個数の処理（集合・場合の数・順列組合）
6120
51
詳説【数学Ａ】第２章 確率
5863
24