Mathematics
Senior High
4行目から5行目へのやり方がわかりません。途中式も入れて教えていただけるとありがたいです。
268 a+6°+c-3abc
)
=(a+b)°-3ab(a+b)+c°-3abc 4
=(a+b)*+c°-3abl(a+b)+¢()
={(a+b)+c}°-3(a+b)c{(a+b)+c}/の
-3ablett
=a+6+c)*-3(a+b)c(a+b+c)
-3ab(a+b+c)
=(a+b+c}{(a+6+c)?-3(a+b)c-3ab} (Q
=(a+b+c}(a?+6?+c?+2ab+2bc+2ca)
-3ca-3bc-3ab|
=(a+b+c)(α°+6?+c?-ab-bc-ca)
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