Mathematics
Senior High
Solved
(1)で2行目から3行目の式になる計算を忘れました。教えてください。
355 次の式を簡単にせよ。
(1) 1og3/32 +1og,54-1og,/g6
(2) (log49-1og163)(logg 16-1og38)
(3) - 16'0g23
00L0ol
log354
log,6
log3/3
log。(2-3)
(1) (与式)=D log3V25 +
log,9
log。(2-3)
log33?
5
= log32? +
log3
1
5
log32 +(log32+3)-2(log32 +1)
= log32 -う
1_2
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ありがとうございました!