Mathematics
Senior High
6分1n(n+1)を括り出す方法を教えてくださいm(_ _)m
(2)(与式)= 2 -4】 e
た=1
k=1
ーn(n+1)(2n+1)-4·号m(n+1)
6
+12+1-2
=+1(2e+112
- +12n-1
1
N(n
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