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(1)の因数分解を教えていただきたいです🙇🏻♀️
7 [改訂版3TRIAL数学Ⅱ 問題88]
次の2次式を,複素数の範囲で因数分解せよ。
(1) 2x?-17x-69
(2) x?-2x-1
(3) x2-2x+2
(4) x+4
(5) 2x2+4xー1
(6) 2x2-3x+2
88 (1) 2次方程式 2x°-17x-69=0 の解は
23
x=-3,
2
23
2.x°-17x-69 =2{x-(-3)](
よって
2
=(x+3)(2x-23)
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