✨ Best Answer ✨
f(x)=(logx)²
f'(x)=(2logx)/x
このことから部分積分
∫f(x)g(x)=F(x)g(x)-∫F(x)g'(x)を用いて
∫x(logx)²dx=x(logx)²/2-∫x(2logx)/xdx
=x(logx)²/2-2∫logxdx=x(logx)²/2-2xlogx+x+c
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
f(x)=(logx)^2にそのまましていいのですね
ありがとうございました！！