Mathematics
Senior High
Solved
nでくくるやり方がわかりません。
そのまま計算してしまいましたが、あっていますか?
(3) (4k³-1)
k=1
4-{{^(n+1)} -n
(1₂5) {2n (4n+4)}³²-n
4n (4n+4)² - h
(16n² +161) ² - n
256h¹+
+ 3²2h²³² +256n²
= 128n² + 16h²³ +1281²
n
64 hª f
8n³
+ 64 h
2
=
"MI
o
32n² + 4h²³² + 32n² = 8h² + n² +8h²³
#
N
(3) Σ (4k³-1)=4Σ k³ - 21
3
n
k=1
k=1
=4
n
n
(4) ►
n
k=1
ETE
2
+-1)}²-
- n
=n{n(n+1)^-1}
=n(n³+2n²+n-1)
Answers
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ありがとうございます!わかりました!