✨ Best Answer ✨
1≡1(mod 5)
5x≡0 (mod 5)
∴16y≡1 (mod 5)
ここで、16y≡y (mod 5)より、
y≡1 (mod 5)
∴y=5k+1
∴x＝-16k-3 (k∈ℤ)
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✨ Best Answer ✨
1≡1(mod 5)
5x≡0 (mod 5)
∴16y≡1 (mod 5)
ここで、16y≡y (mod 5)より、
y≡1 (mod 5)
∴y=5k+1
∴x＝-16k-3 (k∈ℤ)
Users viewing this question
are also looking at these questions 😉
ありがとうございます