Mathematics
Senior High
六番の問題の6√3→2√27になる方法がわかんないです…
1187:12
(5) 与式=
(6) t=
(3) √9+√56
(6)√6-3√3
8-2/15
2
(4) 5=√11-2√/18 =√√(9+2)-2√9-2 =√√9
✓
12-6√3
2
応用問題 73
3-√3
√√2
=
答
√(5+3)-2√5.3
√2
12-2/27
2
3√2-√6
2
学習の記録
=
詳解
D
√5 -
Vi
√(9+3)-
Answers
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