Mathematics
Senior High
Resolved
(3)の式変形を教えてください
できれば紙に書いていただけると嬉しいです
(3) Ź(k³+k)= 2k³ + 2 k={ ½ n(n+1)]} ² + 1/{ n(n+1)
k=1
k=1
1
= n(n+1) { / n(n+1)+1} = n(n+1)(n²+n+2)
LEO KEHONO
2
(4) ²2k=2¹k=2₁²(n-1){(n-1)+1}=n(n-1)
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