Mathematics
Senior High
Solved
どうすると4（√6-√2）分の4（1-√3）になるのか教えてください
cos A =
=
2²+(√6-√2)²-(2√2)²
2.2.(√6-√2)
4(1-√3)
1-√√3
4(√6-√2) √6-√2
C
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