Mathematics
Senior High
Solved
なぜ(2y-3)を前に持ってくるのか教えてください。
月 (2元2次式)
00000
27
+3
(2) 2x²+5xy+2y²+5x+y-3
2x³²+ (54+5) X + 2y² + y − 3
+3
-3)
2)1²+1.5g+5))+(y-1)(2443) 基本 9,13
(y - 3)→→ 4x + (y-11}{2x + ( 24 +3}}
(X+2²=1)(2x +2y+3)
1
=x²+(y+4)x-(y-3)(2y+1)
= {x-(y-3)}{x+(2y+1)}
=(x−y+3)(x+2y+1)
-(y-3) → -y+3
2y+12y+1
A 1
1
1 -(y-3)(2y+1)
(2) 2x²+5xy+2y²+5x+y-3
y+4
B
2y+3→4y+6
y-1→y-1
1
2
2 (2y+3)(y-1)
= 2x²+(5y+5)x+2y²+y-3
=2x²+(5y+5)x+(y−1)(2y+3)
= {x+(2y+3)}{2x+(y-1)}
=(x+2y+3)(2x+y-1)
別解 2次の3つの項を先に因数分解する方法。
5y+5
Answers
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