Mathematics
Senior High

この因数分解の解き方がわかりません。模範解答はこれです。詳しく教えてください!

(4) (a+b+c)(ab+bc+ca)- abc
5=[a+(b+c)}{(b+c)a+bc} - abc =(b+c)a²+{(b+c)² + bc}a+bc(b + c) — abc = (b + c)a²+(b + c)²a+bc(b + c) = (b + c){a²+(b+c)a+bc} =(b+c)(a+b)(a =(a+b)(b+c)(c + c) + a)
因数分解

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