Mathematics
Senior High
この因数分解の解き方がわかりません。模範解答はこれです。詳しく教えてください!
(4) (a+b+c)(ab+bc+ca)- abc
5=[a+(b+c)}{(b+c)a+bc} - abc
=(b+c)a²+{(b+c)² + bc}a+bc(b + c) — abc
= (b + c)a²+(b + c)²a+bc(b + c)
= (b + c){a²+(b+c)a+bc}
=(b+c)(a+b)(a
=(a+b)(b+c)(c
+ c)
+ a)
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