Mathematics
Senior High
なぜこの答えになるのか教えてください！
階差数列の問題です
⑤③
n
n²
(ii) (bm) の一般項は
1
ク 6
である。
bn=
THOMAS
② n-1
62n²-1
{bn} 0.
0.1.
3
3
2n
4
1 n³ JUCⓇn³.
OT+AS-BAT
14, 30
n(n
(ケ)(コスカーサ)
(2
2n-
80 + A0 T
C
$8A9A
X
JA .68o
Answers
No answer yet
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
