(√6+√2)(√3-1)^2+ (√6-√2)(√3+1)^2
= √2 (√3+1)(√3-1)^2+ √2(√3-1)(√3+1)^2
= √2 (3-1)(√3-1)+ √2(3-1)(√3+1)
=2√2 (√3-1)+ 2√2 (√3+1)
=2√2(√3-1+√3+1)
=2√2*√3
=2√6
Mathematics
Senior High
(3)の式を簡単にしてください🙇🏻♀️
(2)
15α-114-14 を因数分解すると、
(3) (√6+√2)(√3-1)+(√6-√2)(√3+1) ²
2
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