Mathematics
Senior High
Resolved
378
(1)写真2枚目のマーカー部分を3枚目の写真のように計算したんですけど、この答えでも丸ですか?
■ 次の不定積分を求めよ。
os 3 x sin 5.g
(3)
*378 (1) fxvx+2dx
(5)
378 (1) √x+2=t とおくと, x+2=2 から
x=t²-2, dx=2tdt
Sx√x+2dx=S (1²-2)t-2tdt=2(t-21³) dt
2
5
15
2
15
2
1/11(31²-10)+C
-(3x-4)(x+2)√√x+2+C
² ( = 2² - ² + ³) + ²
2
²/3/t₁ = = 2 + ² + c
=ts
- 3/² (√x+₂) ==-²4 (√x+₂) ³tc
=/=/(√x+2)
=} (x1₂²)³√x+2₂ - = ²(x+2)√x+2 +
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