Mathematics
Senior High
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この問題の解説の波線部から矢印の式の途中過程が分かりません。
π
2
422 定積分I=See-axsinxdx を求めよ。
= e-sinxdx
3
422 I=
0
-3x sin x
FP
10
ゆえに
+
1
3 Jo
= *
1/3 e ²² - 11/20 - -3x COS X
10
dia to th
=(1-3) -1
KIN
-352²
e-³x cos xdx
3x
よって 101=1/(1-30-1*)
14x20
(1-3e- **)
e-3*sin xdx
= +1
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理解出来ました!ありがとうございます!