Mathematics
Senior High
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一般項を求める問題です。
この解答で合っているか教えてください!
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(3) a₁=1, an+1=-2an+1
C = -20 +1 lut1= -2μm
3c=1.
C = = =
2
Am-C = -2(bu+c) h₁ = a₁ = = = = 1 = = = = = = =
- -
3
C = // zat'α (²
Anti - = = =-2 (au²+ = ² )
ban=an²/3/3とすると
数列{}は公比の等比数列
din = =²3² · (-2)^²-²0
F₂² An = lut = FY
An = 1/2/3 · | -2²/1²h = =+ = = 1/2
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ありがとうございます!!
助かりました!!