✨ Best Answer ✨
四角形BCDFが円の内接四角形なので∠BFD=180°-α
つまり∠AFE=180°-α
よって、α+32°+36°=180°-α
これを解いて、α=56°
同様に円の内接四角形なので∠AFB=α=56°より
β=56°+32°=88°
Mathematics
Senior High
Solved
この問題の求め方を教えてください🙇♂️
α=56°、β=88°です
(3)* A
Op
G
32°
BX B
F
α
C
36°
D
E
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
