Mathematics
Senior High
なぜ答えがこうなるのか分からないので教えてください！！！
(2)
B
a
A
30°
D
E
C
AB=BC, AE=ED
f
(2) ZADB=2BDC A
= <BAC
198 ZACE= ZECD
= LEAD
よって
a=30° +(ZBAC+ ZEAD)
= 30° +(ZADC+ ZACD
= 30° +(180°-ZCAD
=30°+12 (180°-30°)
<=105°
B
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