tanθ＝sinθ/cosθを用いて、
tanθ+1/tanθ
＝sinθ/cosθ+cosθ/sinθ
＝(sin²θ+cos²θ)/sinθcosθ
＝1/sinθcosθ
あとは(1)の値を代入してください
Mathematics
Senior High
(3)の解き方教えて欲しいです！！
問3
sin cos 0 = -
(1) sin Ocos0
√5
2
のとき、次の式の値を求めよ。
(2) sin 30 - cos30
(3) tan 0 +
1
tan 0
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