Mathematics
Senior High
複素数平面の式の変形、どうやってやっているのか教えてください🙇
b
b-c
ang (2)= arg (c)
a-c
である。よって
arg
[a(c-b)]
b(c-a)
=
arg
b-c
a-c
arg
a
=
0
Answers
No answer yet
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ｂ】ベクトルとその演算
3254
10
詳説【数学Ｂ】ベクトルと図形
2587
1