✨ Best Answer ✨
tan²θ-tan²θsin²θ-sin²θ
＝tan²θ-sin²θ(tan²θ+1)
＝tan²θ-sin²θ・1/cos²θ
＝tan²θ-tan²θ
＝0
Mathematics
Senior High
Solved
(３)を教えていただきたいです
(1) (251110
(2)
(3)
+OCO
(T
3sin 7
2
(1-sin)(1+
tan²0-tan²0 sin 20-sin ²0
sin ) -
ZCOSO)
1
1+tan²0
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