✨ Best Answer ✨
2Θ²/(1-cosΘ)={2Θ²/(1-cosΘ)}×(1+cosΘ)/(1+cosΘ)=2Θ²(1+cosΘ)/(1-cos²Θ)=2(1+cosΘ)×Θ²/sin²Θ=2(1+cosΘ)×(Θ/sinΘ)²
lim(Θ→0)2(1+cosΘ)=2×2=4であり
lim(Θ→0)Θ/sinΘ=1なので
lim(Θ→0)2Θ²/(1-cosΘ)=4×1²=4
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