Mathematics
Senior High
Resolved
この式の右の列、上から2列目から3列目にいったところどうやってやったかわからないです。
n
n
=4n(n+1)+3n = n(4n+7)
n
(2) k(k+5)=(k²+5k) = k² +5 k
k=1
=
空+52
k=1
n(n+1)(2n+1)+5.
k=1
k=1
1
=
6
1/12m(n+1)
==
6
n(n+1)(2n+1)+15}
1
===—=— n ( n + 1 ) (2n + 16) = = = = n ( n +1)(n+8)
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