Mathematics
Senior High
Resolved
この計算どうやりますか？
(1) (n=5C1 nC₁.
=
2·5⋅n
解答
+5C2
(n+5)(n+4)
10n
(n+5)(n+4)
Dn+1=
10(n+1)
(n+5)(n+4)
pn
(2) =(n+6)(n+5)
X
10n
(n+1)(n+4)
n(n+6)
4-n
=1+n(n+6)
n(n+6)
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