Mathematics
Senior High
ここの計算方法を教えて欲しいです！🙏🏻💦
x=1のとき
(1-x)S=1+
3x (1-x-1)
1-x
-(3n-2)x"
tn+12
D
1+2x- (3n+1)x"+(3n-2)xn+1
よって, x≠1のとき
1-x
1
S=-
1+2x-(3n+1)x"+(3n-2)xn+1
(1-x)2
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