Mathematics
Senior High
Solved
真ん中の式
通分するみたいなんですけどやり方がわかりません
途中式的なのもらえませんか
n(3n+5)
4(n+1)(n+2)
=
=
2 2 (n+1)(n+2)
TURA
1
12
2
3(n+1)(n+2)-2(2n+3)
32(n+1)(n+2)
①の辺に1
(4)
k=1
k(k+1)(k+2)
n
1
=
k=1 2 (k(k+1)
1
(k+1)(k+2)
Answers
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ありがとうございます!