√3x-1<√5x-√15
⇔(√3-√5)x<1-√15
⇔x>(1-√15)/(√3-√5)
⇔x>(1-√15)(√3+√5)/-2
⇔x>(√3+√5-3√5-5√3)/-2
⇔x>-2(2√3+√5)/-2
⇔x<(2√3+√5)
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