Chemistry
Senior High
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(1) CH3COOHog: 0.10mol/LのPHはいくら?(有効数
-5
<1, Ka = 2.7×10 melk log 2.7-0.43
[H+] = √CKa
-3
= √217 3 ml/1
00x22x105 /2x10 minh
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すごく分かりやすいです!ありがとうございます🙇♀️