Mathematics
Senior High
Solved
なぜt-2π=xと置くという考えになるのですか
次の極限を求めよ。
sint
t-2л
(1) lim72-42
[東京電機大]
1) t-2π=x とおくと
t→ 2 のとき
x0
lim
sint
よって
lim
sin(x+2)
sinx
t-2π t²-4π²
=lim
2
x―0 (x+2л)²-4π²
=lim
x-0 x²+4πx
-lim, sinx
=lim
1
1
=
x-0
x
x+4π
0+4π
4π
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