✨ Best Answer ✨
∫[1→3](9x^2-2x)dx-∫[2→3](9x^2-2x)dx
=∫[1→3](9x^2-2x)dx+∫[3→2](9x^2-2x)dx
=∫[1→2](9x^2-2x)dx
=[3x^3-x^2][1,2]
=(24-4)-(3-1)
=18…(答)
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