Mathematics
Senior High
Resolved

ここの解き方を教えてください!

19.0≤02のとき,次の方程式、不等式を解け。 (1) 2√3sin0-3 sin g <- 1/135 2√3 (2) 2c 2(1-

Answers

Were you able to resolve your confusion?

Users viewing this question
are also looking at these questions 😉