Mathematics
Senior High
Resolved
ここの解き方を教えてください!
19.0≤02のとき,次の方程式、不等式を解け。
(1) 2√3sin0-3
sin g <- 1/135
2√3
(2) 2c
2(1-
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉

ありがとうございます!すっきりしました