1. 圓心為(2,-3),半徑為2√5
2. L1、L2斜率為2,可寫出L1:2x-y=k1,L2:2x-y=k2
3. 算圓心到直線距離公式可求得k有兩個解,分別為k1、k2的值
4. y=0帶入L1、L2,算出各自的x值,最後求x差值
可以看看圖裡的算式有沒有哪裡看不懂
Mathematics
Senior High
不會
5. 坐標平面上,已知兩直線L1,L2的斜率均為2,且同時與圓C:(x-2)+(y+3)=20
相切,若L1,L2分別與x軸交於4,B兩點,則AB的長度為10
(2,-3) 1=
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