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Answers

半径1の円上の点が(cosθ,sinθ)と表されるので(2cosθ,2sinθ)ならば半径2の円。
三角関数の合成とか使わないです!
OP=x+yとしていませんか?
OP²=x²+y²=2²(cos²θ+sin²θ)=4, OP=2

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