✨ Best Answer ✨
除法原理
2x³ + ax² + 8x + 5 = (x² + x + 3)(2x + 1) + (x + b)
分配律展開
2x³ + ax² + 8x + 5 = (2x³ + 3x² + 7x + 3) + (x + b)
同類項合併
2x³ + ax² + 8x + 5 = 2x³ + 3x² + 8x + (b+3)
多項式相等，比較係數
a = 3 , 5 = (b+3)
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