（1)
連線AM、BM
畢氏定理過程我就省略
AM=BM=12
MN即ΔABM以AB為底的高
三邊12 12 8畢氏定理
MN=8√2
(2)
一樣用ΔABM
兩面角即<AMB
餘弦定理cosθ=12²+12²-8² / 2*12*12=7/9
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
[107學測]數學觀念總整理(上)
5241
40
[106學測]更新囉!!!一到四冊超強大數學
4022
44
[107學測]數學觀念總整理(下)
3739
18
[107學測]學測數學超重點
1868
8