Mathematics
Senior High
(6)と(7)どこで間違えてますか?
(5)* (a2-ab+2b)(a 2 +ab+262)
=
=
=
(6) (2a-56-3)(2a-56+2)
{(a=+2b²)-ab} {(a²+2b³)+ab} = {(za-5b)-3} {iza-5b)+2}
29
(a²+262) 2-a²b
= a++4a²b² + 464 -a²b²
+4a²b²+4b+
=
α + + 3a²b² +46 ²
(7) (3x+3y-2x+y+ z)
=(x+2)}{(x+2}
=3(x+y)² -z²
= 3(x²+2x3+ y²)-z²
=3つ2+6xy+3y3-32
3x² + 3y² - 2²+6XY +27x+23x
=(2a-5b)2-6
=4a²-20 ab+2562-6
4a²-20ab + 256²-2α+56-6
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
数学ⅠA公式集
5730
20
詳説【数学Ⅱ】第3章 三角関数(前半)~一般角の三角関数~
4913
18
詳説【数学Ⅰ】第三章 図形と計量(前半)~鋭角鈍角の三角比~
4580
11
詳説【数学A】第3章 平面図形
3627
16

