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設前面 m 次，後面 n 次
m + n = 6
因為要常數項，需要的是 (x²)ᵐ(1/x)ⁿ 剛好會消掉變常數
從指數律來看就是 2m - n = 0
解方程組得到 m = 2 , n = 4
所以會產生常數項的部分就是
C⁶₂ (5x²)² (2/x)⁴
係數乘開就好了
Mathematics
Senior High
Solved
這題要怎麼算？
類題練習1-2
5x-2)展開式中,常數項為?
x
(A) 3200 (B) 3260 (C) 4200 (D) 6000 (E) 7200
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