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両辺に 3(x²-1) =3(x+1)(x-1) を掛ける
3(x+1)-2×3=x²-1
整理して
x²-3x+2=0
(x-1)(x-2)=0
x=1, 2
x≠1, x≠-1 なので x=2
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両辺に 3(x²-1) =3(x+1)(x-1) を掛ける
3(x+1)-2×3=x²-1
整理して
x²-3x+2=0
(x-1)(x-2)=0
x=1, 2
x≠1, x≠-1 なので x=2
Users viewing this question
are also looking at these questions 😉
わかりやすく教えていただきありがとうございます。