(x+2y-3z)(x-2y+3z)
=[x+(2y-3z)][x-(2y-3z)]
=x^2-(2y-3z)^2
=x^2-4y^2-9z^2+12yz
みたいな感じですかね^_^
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
8980
117
詳説【数学Ⅰ】第二章 ２次関数（後半）～最大・最小・不等式～
6128
25
数学ⅠA公式集
5730
20
詳説【数学Ⅱ】第３章 三角関数（前半）～一般角の三角関数～
4913
18
ありがとうございます！！