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Answers
2x^2-5xy-3y^2+7y-2
=2x^2-5xy-(3y^2-7y+2)
=2x^2-5xy-(3y-1)(y-2)
ここで、2×-(3y-1)+1×(y-2)=-6y+2+y-2=-5y、なので
=(2x+(y-2))(x-(3y-1))
=(2x+y-2)(x-3y+1)
Were you able to resolve your confusion?
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