Mathematics
Junior High

EF の求め方、教えてください(・_・;)

答えは2(cm)でした

の7 大の へABC で, AD = DB, AE = EC でぁ ぅ。 BC王8cm, BE =6cm のとき, DE EE の 丘CE ク (4

Answers

△DEF∽△CBF
DE:CB=1:2なので
EF:BF=1:2
BE:EF=3:1
=6cm:2cm
よってEFは2cm

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