✨ Best Answer ✨
(x−α)(x−β)(x−γ)
=x³−(α+β+γ)x²+(αβ+βγ+γα)x−αβγ
です。😀
根気よく展開するなら
(t−1)(t−2)(t−3)
=(t²−3t+2)(t−3)
=t³−6t²+11t−6
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ありがとうございます！！