Question

0210723

マーカー部分の式はどのように出しますか

=
= [
α
=
=
a
==
=
α
B
(x − a)x(x − B) dx
-
1
(x-a)(x - 3)(x - B+B) dx
[1/(x − α)(x − 3)³
12
(x − x)(x − ß)² dx +
1
[ = 2
12
- (x − B) 4
(²
1
- 9) ³] ² - / ² / 3 (2 - 9 )³ dx + 6
S B) BS²
α
B
[²³ B(x − a) (x − 3) dx
α
12
(a − B) ³
B
+ ² ( 1² (²
3)4] h ( [1/(2* —- α) (²
(z − a) (x − 9)²¹] ²
B
·(x
- [ ²³
-1892²] " - - / 1² / (2 - 1297² dz)
(x B) dx
α
(a − B)¹ - B
[ 1 (2-
- 3 [ 1 (2-1)³] "
·(x B)3
α
B
(a − B)¹ + 2/(a− B) ³
-
(x − a) (x − B) dx